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Ejercicios resueltos de elemento, Apuntes de Matemáticas

resuelto y apuntes de tal y toda clase de datos interesantes

Tipo: Apuntes

2021/2022

Subido el 14/04/2022

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1 clase 1 2022 1
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1.2 clase Frenos de zapata corta part2 11
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2 clase 2 - 2022 19
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2.2 clase 4.2 31
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3 clase 5.1 42
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4 Clase 6 54
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5 clase 7 embragues 64
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6 Clase repaso 75
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1 clase 1 2022 1 ···································································································································································································································································································

1.2 clase Frenos de zapata corta part2 11 ···························································································································································································································································

2 clase 2 - 2022 ······························································································································································································································································································· 19

2.2 clase 4.2 31 ····································································································································································································································································································

3 clase 5.1 42 ·······································································································································································································································································································

4 Clase 6 54 ·········································································································································································································································································································

5 clase 7 embragues 64 ·······················································································································································································································································································

6 Clase repaso ································································································································································································································································································ 75

FRENOS DE ZAPATA

CORTA

Aux. Univ. ÑUFLO FLORES INDER ADALID

0

o

𝐴

𝑎

𝑎

𝑎𝑑𝑚

𝑎𝑑𝑚

𝐴

𝑎𝑑𝑚

𝐴

Ejm.2 Calcule la fuerza de actuación que se requiere

para que el freno de la balata corta de la figura pueda

generar una torsión

𝑻 = 𝟏𝟓𝟎 𝒍𝒃 𝒇

− 𝒑𝒊𝒆. 𝑼𝒕𝒊𝒍𝒊𝒛𝒆 𝒍𝒐𝒔 𝒔𝒊𝒈𝒖𝒊𝒆𝒏𝒕𝒆𝒔 𝒅𝒂𝒕𝒐𝒔:

𝑫 = 𝟏𝟐𝒑𝒍𝒈, 𝒃 = 𝟏𝟒𝒑𝒍𝒈, 𝒄 = 𝟐𝟓𝒑𝒍𝒈, 𝝁 = 𝟎, 𝟐𝟓, 𝒂 = 𝟒𝒑𝒍𝒈.

También determine la dimensión de “a” que se necesita

para que el freno actúe por si mismo, las reacciones en

el pivote A y las reacciones del eje del motor

Este es un freno de zapata corta por tanto

debemos dibujar el diagrama de cuerpo libre

𝑓

c = 25 𝑝𝑙𝑔

u = 0 , 25 𝑎 = 4𝑝𝑙𝑔

FRENOS DE ZAPATA CORTA

𝑥

𝑦

𝑥

𝑦

o

𝑜

o

Las reacciones en la articulación A: Las reacciones en el eje del tambor:

𝑥

𝑦

𝑥

𝑥

𝑦

𝑦

𝑥

𝑓

𝑥

𝑓

𝑦

𝑓

𝑌

𝑓

𝑥

𝑦

𝑥

𝑥

𝑦

𝑦

𝑥

𝑓

𝑦

𝑓

𝑥

𝑓

Es un freno de zapata corta entonces realizamos

siempre el diagrama de cuerpo libre

c)𝐹( 𝑠𝑒𝑛𝑡. 𝑎𝑛𝑡𝑖ℎ𝑜𝑟𝑎𝑟𝑖𝑜) =??

o

𝑜

Ejm.3 El tambor de un freno de 350 mm de radio hace

contacto con una zapata simple como se muestra en la

figura y sostiene un momento de 𝟐𝟐𝟓 𝑵𝒎 de torque. Para

un coeficiente de rozamiento de 𝟎, 𝟑 Determinar:

a)La fuerza Normal sobre la zapata

b) La fuerza F que debe aplicarse al freno si la rotación

es en sentido del movimiento de las agujas del reloj

c) La fuerza F que debe aplicarse al freno si la rotación

es en sentido contrario al movimiento de las agujas del

reloj

Indique si son frenos autoenergizantes o desenergizantes

Como el signo del momento debido a fricción y el

momento de la fuerza actuante (accionamiento)

son iguales es un freno autoenergizante

Analizar que tipo de frenos son cada configuración

P.0 A modo de práctica, que comportamiento

presenta cada una de las articulaciones. ¿ Serán

Energizantes o desenergizantes?

P.2 El tambor de un freno de 14 plg de radio hace

contacto con una zapata simple como se muestra en la

figura y sostiene un momento de 𝟐𝟎𝟎 𝒍𝒃 − 𝒑𝒍𝒈 de torque.

Para un coeficiente de rozamiento de 𝟎, 𝟑 Determinar:

a)La fuerza Normal sobre la zapata

b) La fuerza F que debe aplicarse al freno si la rotación

es en sentido del movimiento de las agujas del reloj

c) La fuerza F que debe aplicarse al freno si la rotación

es en sentido contrario al movimiento de las agujas del

reloj

d) El cambio necesario de la holgura de 2 plg para que

el freno funcione como autobloqueante

𝑟𝑝𝑡𝑎. −𝑎) 47 ,62𝑙𝑏𝑓

𝑏) 17 , 73 𝑙𝑏𝑓

𝑐) 19 , 31 𝑙𝑏𝑓

𝑑) 46 , 67 𝑝𝑙𝑔

P.1 Determinar el momento que puede resistir

El freno simple mostrado en la figura si el coeficiente

de rozamiento es 0,

𝑟𝑝𝑡𝑎. − 438 𝑙𝑏𝑓 − 𝑝𝑙𝑔

Problemas propuestos

Es un freno de zapata corta entonces realizamos

Su diagrama de cuerpo libre

𝑎

o

𝑂

𝑎

𝑎

Ejm. 3 En la figura se muestra un freno con

diámetro del tambor es D y el ángulo de

contacto es de 𝜽 = 32 , 7 °. Si la fuerza de

operación que se aplica al extremo de una

palanca es 𝑭

𝒂

y el coeficiente de fricción

entre el tambor y la zapata corta es 𝝁 = 𝟏/𝟐 ,

además la geometría del Freno es a, 𝒃 =

𝟓

𝟗

𝟏

𝟗

𝒂 , determine a) el par que

puede ser transmitido por el freno de

bloque. b) la presión admisible en la

superficie de contacto.

1

𝑎

0

o

𝐴

𝑎

𝑎

𝑎𝑑𝑚

𝑎𝑑𝑚

𝐴

𝑎𝑑𝑚

𝐴

Ejm.4 La figura muestra un freno de tambor con doble

zapata corta. Determine su capacidad de torque y la

fuerza aplicada requerida para

𝒂 = 𝟑𝟎 𝒄𝒎 𝒃 = 𝟐𝟎 𝒄𝒎 𝒆 = 𝟖 𝒄𝒎 𝒓 = 𝟏𝟔 𝒄𝒎 𝒚 𝜽 = 𝟐𝟎°.

Suponga 𝑷 𝒎á𝒙

= 𝟏 𝑴𝑷𝒂, 𝒂𝒏𝒄𝒉𝒐 = 𝟓 𝒄𝒎 𝒚 𝒇 = 𝟎, 𝟑

Es un freno de zapata corta

por ende, debemos dibujar el

diagrama de cuerpo libre

𝑚á𝑥

1

FRENOS DE ZAPATA CORTA

𝑥

𝑦

1

1

𝑁 1

1

o

2

2

2

2

2

1

1

1

𝑁 1

1

o

2

2

2

2

2

𝑂 1

1

1

1

Zapata Superior

Hallemos la Factuac. en función de la normal

1

1

1 𝑁

1

o

2

2

𝑜

2

1

1

2

𝑇 = 28963 [𝑁 − 𝑐𝑚]

𝑇 = 289 , 6 [𝑁 − 𝑚]

P.3 La figura muestra un freno de tambor con doble

zapata corta. Determine su capacidad de torque y la

fuerza aplicada requerida para

𝒂 = 𝟏𝟐 , b=8" , e=3" , r=6" 𝒚 𝜽 = 𝟐𝟓°.

¿Qué valor de c hará que se autobloquee?. Suponga

𝑷 𝒎á𝒙

= 𝟐𝟎𝟎 𝑷𝒔𝒊, 𝒂𝒏𝒄𝒉𝒐 = 𝟐𝒑𝒍𝒈𝒚 𝒇 = 𝟎, 𝟐𝟖

Problemas propuestos

𝑟𝑝𝑡𝑎. −𝐹 = 624 , 7 [𝑙𝑏𝑓]

𝑇 = 3184 [𝑙𝑏𝑓 − 𝑝𝑙𝑔]

𝑐 = 28 ,6𝑝𝑙𝑔

FRENOS LARGOS DE

EXPANSIÓN y

ZAPATA INTERNA

Aux. Univ. ÑUFLO FLORES

INDER ADALID