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Solving Rational Equations: A Comprehensive Guide with Examples, Lecture notes of Algebra

Example 1: Solve the following equation. If there is no solution, write. NO SOLUTION. If there are infinitely many solutions, list the restrictions using the ...

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16-week Lesson 11 (8-week Lesson 9) Solving Rational Equations
1
Rational equations:
- equations containing one or more rational expressions
o remember from Lesson 7 that rational expressions are simply
fractions containing polynomials, so each equation we work
with today will contain fractions
o Example: ๐‘ฅ+4
5๐‘ฅโˆ’3 โˆ’2๐‘ฅโˆ’5
10๐‘ฅ+7 = 0
- since we are working with equations now, rather than expressions, we
do NOT have to work with the fractions; instead we can eliminate
them using multiplication
o in the case of ๐‘ฅ+4
5๐‘ฅโˆ’3 โˆ’2๐‘ฅโˆ’5
10๐‘ฅ+7 = 0 we could multiply both sides of
the equation by 5๐‘ฅ โˆ’ 3 and 10๐‘ฅ + 7 to eliminate the fractions
o if you prefer to get a common denominator and work with the
fractions, you may, but I do not recommend it
- keep in mind that even if we eliminate the fractions, we still cannot
have any answers that result in a denominator of zero
o in the case of ๐‘ฅ+4
5๐‘ฅโˆ’3 โˆ’2๐‘ฅโˆ’5
10๐‘ฅ+7 = 0 , ๐‘ฅ โ‰  3
5 or ๐‘ฅ โ‰  โˆ’ 7
10
๏‚ง 5๐‘ฅ โˆ’ 3 โ‰  0 โ–  10๐‘ฅ + 7 โ‰  0
5๐‘ฅ โ‰  3 10๐‘ฅ โ‰  โˆ’7
๐‘ฅ โ‰  3
5 ๐‘ฅ โ‰  โˆ’ 7
10
o the answer to ๐‘ฅ+4
5๐‘ฅโˆ’3 โˆ’2๐‘ฅโˆ’5
10๐‘ฅ+7 = 0 is ๐‘ฅ = โˆ’1
6, and since โˆ’1
6 does
not result in a denominator or zero, it is a valid answer
- ALWAYS exclude any values that make the denominator zero
- ALWAYS make sure that your solution(s) is/are not excluded
pf3
pf4
pf5

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Download Solving Rational Equations: A Comprehensive Guide with Examples and more Lecture notes Algebra in PDF only on Docsity!

Rational equations:

  • equations containing one or more rational expressions

o remember from Lesson 7 that rational expressions are simply

fractions containing polynomials, so each equation we work

with today will contain fractions

o Example:

๐‘ฅ+ 4

5 ๐‘ฅโˆ’ 3

2 ๐‘ฅโˆ’ 5

10 ๐‘ฅ+ 7

  • since we are working with equations now, rather than expressions, we

do NOT have to work with the fractions; instead we can eliminate

them using multiplication

o in the case of

๐‘ฅ+ 4

5 ๐‘ฅโˆ’ 3

2 ๐‘ฅโˆ’ 5

10 ๐‘ฅ+ 7

= 0 we could multiply both sides of

the equation by 5 ๐‘ฅ โˆ’ 3 and 10 ๐‘ฅ + 7 to eliminate the fractions

o if you prefer to get a common denominator and work with the

fractions, you may, but I do not recommend it

  • keep in mind that even if we eliminate the fractions, we still cannot

have any answers that result in a denominator of zero

o in the case of

๐‘ฅ+ 4

5 ๐‘ฅโˆ’ 3

2 ๐‘ฅโˆ’ 5

10 ๐‘ฅ+ 7

3

5

or ๐‘ฅ โ‰  โˆ’

7

10

3

5

7

10

o the answer to

๐‘ฅ+ 4

5 ๐‘ฅโˆ’ 3

2 ๐‘ฅโˆ’ 5

10 ๐‘ฅ+ 7

= 0 is ๐‘ฅ = โˆ’

1

6

, and since โˆ’

1

6

does

not result in a denominator or zero, it is a valid answer

  • ALWAYS exclude any values that make the denominator zero
  • ALWAYS make sure that your solution(s) is/are not excluded

Steps for Solving Rational Equations:

  1. factor all denominators
  2. multiply both sides of the equation by the least common multiple of

all the denominators to eliminate the fractions

  1. distribute and combine like terms
  2. isolate the variable
  3. verify that your solution(s) is/are not restricted

Example 1: Solve the following equation. If there is no solution, write

NO SOLUTION. If there are infinitely many solutions, list the restrictions

using the notation ๐‘… โˆ’

(all real numbers except).

2

a.

Example 3: Solve the following equation. If there is no solution, write

NO SOLUTION. If there are infinitely many solutions, list the restrictions

using the notation ๐‘… โˆ’

(all real numbers except).

2

Be sure to ALWAYS check your answers in the original equation to be

sure they do not result in a denominator of zero. If they do, they are not

valid answers. If you only have one solution, and it is not valid, then you

now have NO SOLUTION. No solution does not mean we didnโ€™t come

up with any answers (on Example 3 we did, ๐‘ฅ = โˆ’ 2 ); it means the answer

we came up with is invalid because it makes a denominator equal to zero.

Example 4 : Solve the following equationS. If there is no solution, write

NO SOLUTION. If there are infinitely many solutions, list the restrictions

using the notation ๐‘… โˆ’

(all real numbers except).

a. 17 โˆ’

3

๐‘ฅ

= โˆ’ 16 b.

3 ๐‘ฅ+ 1

6 ๐‘ฅโˆ’ 1

2 ๐‘ฅ+ 5

4 ๐‘ฅโˆ’ 13

3

๐‘ฅ

= โˆ’ 16 b.

3 ๐‘ฅ+ 1

6 ๐‘ฅโˆ’ 1

2 ๐‘ฅ+ 5

4 ๐‘ฅโˆ’ 13

b. B.๐‘ฅ(

3

๐‘ฅ

3 ๐‘ฅ+ 1

6 ๐‘ฅโˆ’ 1

) = (

2 ๐‘ฅ+ 5

4 ๐‘ฅโˆ’ 13

) ( 4 ๐‘ฅ โˆ’ 13 )( 6 ๐‘ฅ โˆ’ 1 )

2

2

3

33

2

2

๐Ÿ

๐Ÿ๐Ÿ

๐Ÿ–

๐Ÿ”๐Ÿ‘

c.

5

2 ๐‘ฅ+ 3

4

2 ๐‘ฅโˆ’ 3

14 ๐‘ฅ+ 3

4 ๐‘ฅ

2

โˆ’ 9

d.

6

๐‘ฅ+ 3

5

๐‘ฅโˆ’ 2

โˆ’ 20

๐‘ฅ

2

+๐‘ฅโˆ’ 6

5

2 ๐‘ฅ+ 3

4

2 ๐‘ฅโˆ’ 3

14 ๐‘ฅ+ 3

4 ๐‘ฅ

2

โˆ’ 9

d.

6

๐‘ฅ+ 3

5

๐‘ฅโˆ’ 2

โˆ’ 20

๐‘ฅ

2

+๐‘ฅโˆ’ 6

d.

Answers to Examples:

3. ๐‘๐‘‚ ๐‘†๐‘‚๐ฟ๐‘ˆ๐‘‡๐ผ๐‘‚๐‘ ; 4 a.

1

11

; 4b. ๐‘ฅ = โˆ’

8

63

4c. ๐‘๐‘‚ ๐‘†๐‘‚๐ฟ๐‘ˆ๐‘‡๐ผ๐‘‚๐‘ ; 4d. ๐‘ฅ = 7 ;

4e. ๐ผ๐‘๐น๐ผ๐‘๐ผ๐‘‡๐ธ๐ฟ๐‘Œ ๐‘€๐ด๐‘๐‘Œ ๐‘†๐‘‚๐ฟ๐‘ˆ๐‘‡๐ผ๐‘‚๐‘๐‘†, โ„ โˆ’ {

1

2

4f. ๐‘๐‘‚ ๐‘†๐‘‚๐ฟ๐‘ˆ๐‘‡๐ผ๐‘‚๐‘ ;