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Modeling Of The Double Tank Process-Fluid Mechanics-Handout, Exercises of Fluid Mechanics

This handout is related to Fluid Mechanics course. It was distributed by Sajiv Janam at AMET University. It includes: Modeling, Double-tank, Process, Derivation, Linearization, Differential, Equations, Laplace, Transforms, Nonlinear

Typology: Exercises

2011/2012

Uploaded on 07/17/2012

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Modeling of the Double-tank process
We will here briefly derive the transfer functions from control signal to measure-
ment signal for the Double-tank process. First, nonlinear differential equations
that describe the system are stated. These are linearized around a chosen oper-
ating point, and Laplace transforms are taken to obtain the transfer functions.
Finally, parameter values are given.
Derivation and linearization of differential equations
Mass balance and Bernoulli’s law give the following differential equation for a
tank with cross-section Aand outflow area a.
Adh
dt −a
p2gh+qin
We now assume that the flow generated by the pump is proportional to the
applied voltage, i.e.
qpump ku
This is motivated by the fact that the time constant of the pump is "small"
as compared to the tank dynamics. In the same way, assume that the level
measurement signal yis proportional to the true level h. Thus we write
ykch
Since the outflow from the upper tank is the inflow to the lower tank we
get the following system of nonlinear differential equations describing the tank
process
dh1
dt −
α
1
p2gh1+
β
u
dh2
dt
α
1p2gh1
α
2p2gh2(1)
where h1and h2are the water levels in the upper and lower tank respectively.
We also define
α
iai
Aiand
β
k
A1.
Linearizing around an operating point1(h0
1,h0
2)yields
dh1
dt −1
T
1
h
1+
β
u
d
h
2
dt 1
T1
h11
T2
h2(2)
where we have introduced
T11
α
1s2h0
1
g,T21
α
2s2h0
2
g
1Note that from (1)we have the condition h0
1
h0
2
(
α
2
α
1)
2
.
1
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Modeling of the Double-tank process

We will here briefly derive the transfer functions from control signal to measure- ment signal for the Double-tank process. First, nonlinear differential equations that describe the system are stated. These are linearized around a chosen oper- ating point, and Laplace transforms are taken to obtain the transfer functions. Finally, parameter values are given.

Derivation and linearization of differential equations

Mass balance and Bernoulli’s law give the following differential equation for a tank with cross-section A and outflow area a.

A

dh dt

 − a

2 gh + q (^) in

We now assume that the flow generated by the pump is proportional to the applied voltage, i.e.

q (^) pump  ku

This is motivated by the fact that the time constant of the pump is "small" as compared to the tank dynamics. In the same way, assume that the level measurement signal y is proportional to the true level h. Thus we write

y  k (^) c h

Since the outflow from the upper tank is the inflow to the lower tank we get the following system of nonlinear differential equations describing the tank process

dh 1 dt

 − α (^1)

2 gh 1 + β u

dh 2 dt

 α (^1)

2 gh 1 − α (^2)

2 gh 2 ( 1 )

where h 1 and h 2 are the water levels in the upper and lower tank respectively. We also define α (^) i  aA^ i (^) i and β  (^) Ak 1.

Linearizing around an operating point^1 ( h^01 , h^02 ) yields

dh 1 dt

T 1

h 1 + β ∆ u

dh 2 dt

T 1

h 1 −

T 2

h 2 ( 2 )

where we have introduced

T 1 

α (^1)

2 h^01 g

, T 2 

α (^2)

2 h^02 g

(^1) Note that from ( 1 ) we have the condition h^01 h^02  (

α (^2) α 1 )

(^2).

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Transfer functions

Taking the Laplace transform and also considering the sensor conversion we arrive at the following transfer functions from control signal to measurement signals

Y 1 ( s ) 

k (^) p T 1 1 + sT 1

U ( s )

Y 2 ( s ) 

k (^) p T 2 ( 1 + sT 1 )( 1 + sT 2 )

U ( s ) ( 3 )

with k (^) p  β ⋅ k (^) c. Y 1 , Y 2 and U denote the Laplace transforms of the level mea- surements and the control signal.

Parameter values

The physical constants have the following values

A  2734 ⋅ 10 −^6 m^2 a  7 ⋅ 10 −^6 m^2 k  2. 7 ⋅ 10 −^6 m^3 /( V s ) k (^) c  50 V / m

thus yielding the theoretical values

α 1  α 2  2. 6 ⋅ 10 −^3 β  0. 99 ⋅ 10 −^3 m /( V s )

However, due to flow losses and other process variations, we have to adjust these values. Simple experiments show that reasonable values are

α  2. 1 ⋅ 10 −^3 β  1. 1 ⋅ 10 −^3 m /( V s )

Specifying an operating point of h^01  h^02  0 .1 m and using the experimental values we obtain

T 1  T 2  68 s k (^) p  0. 055 s −^1

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