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BJT and FET Frequency response, Lecture notes of Electronics

Lesson 3 of Electronic Circuits

Typology: Lecture notes

2019/2020

Uploaded on 11/28/2020

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BJT & JFET FREQUENCY RESPONSE
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BJT & JFET FREQUENCY RESPONSE

FREQUENCY EFFECTS

๏ƒ’ AC Amplifiers โ€“ the voltage gain decreases when the input frequency is too low or too high ๏ƒ’ DC Amplifiers โ€“ have voltage gain all the way down to zero frequency ๏ƒ’ Decibels โ€“ used to describe the decrease in voltage gain ๏ƒ’ Bode Plot โ€“ used to graph the response of an amplifier

FREQUENCY RESPONSE OF AN AC AMPLIFIER

๏ƒ’ Middle Range of Frequencies โ€“ voltage gain is maximum / normal operation ๏ƒ’ Low Frequencies โ€“ voltage gain decreases because the coupling and bypass capacitors no longer act like short circuits ๏ƒ’ High Frequencies โ€“ voltage gain decreases due to the internal capacitances across a transistor junctions and due to stray-wiring capacitance

FREQUENCY RESPONSE OF AN AC AMPLIFIER

๏ƒ’ Cut-off Frequencies โ€“ the frequencies at which the voltage gain equals 0.707 of its maximum values ๏ƒ’ f 1 and f 2

  • lower cut-off frequency and upper cut-off frequency respectively ๏ƒ’ also referred to as the half-power frequencies

FREQUENCY RESPONSE OF AN AC AMPLIFIER

๏ƒ’ Outside the Mid-band ๏ƒ’ Dominant Capacitor โ€“ one that is more important than all others in determining the cut-off frequency

FREQUENCY RESPONSE OF AN AC AMPLIFIER

๏ƒ’ Midband: ๏ƒ’ Below Midband: ๏ƒ’ Above Midband:

RESPONSE OF A DC AMPLIFIER

๏ƒ’ two important characteristics - A V(mid) and f 2 ๏ƒ’ dc amplifier โ€“ more widely used than the ac amplifier because most amplifiers are now designed with op-amps instead of with discrete transistors

RESPONSE OF A DC AMPLIFIER

๏ƒ’ Between Midband and Cut-off

EXAMPLES

๏ƒ’ Example: The figure shows a 741C, an op-amp with a midband voltage gain of 100,000. If f 2 =10Hz, what does the frequency response look like?

DECIBEL POWER GAIN

๏ƒ’ Decibels โ€“ a useful method for describing frequency response ๏ƒ’ Review of Logarithms x = 10 y y = log 10 x = log x

  • y is the logarithm (or exponent) of 10 that gives x ๏ƒ’ Using Calculator that has a common log function y = log 10 y = log 0. y = log 100 y = log 0. y = log 1000 y = log 0. ๏ƒ’ as x increases / decreases by a factor of 10, y increases/decreases by 1

DECIBEL POWER GAIN

๏ƒ’ Two Useful Properties of Decibel Power Gain: ๏ƒ‰ Each time the ordinary power gain increases (decreases) by a factor of 2, the decibel power gain increases (decreases) by 3dB. ๏ƒ‰ Each time the ordinary power gain increases (decreases) by a factor of 10, the decibel power gain increases (decreases) by 10 dB. Examples: Calculate the decibel power gain for the following values: Ap = 1, 2, 4, and 8 A p = 1, 0.5, 0.25, and 0. Ap = 1, 10, 100, 1nd 1000 Ap = 1, 0.1, 0.01, and 0.

DECIBEL VOLTAGE GAIN

๏ƒ’ Voltage Gain โ€“ the output voltage divided by the input voltage A V = v out / v in ๏ƒ’ Decibel Voltage Gain A V(dB) = 20 log A V example: What is the decibel voltage gain if AV=100,000; 100; 100,000, ๏ƒ’ Basic Rules for Voltage Gain: ๏ƒ‰ Each time the voltage gain increases(decreases) by a factor of 2, the decibel voltage gain increases(decreases) by 6dB. ๏ƒ‰ Each time the voltage gain increases(decreases) by a factor of 10, the decibel voltage gain increases(decreases) by 20 dB.

DECIBEL VOLTAGE GAIN

๏ƒ’ Decibel Voltage Gain A V(dB) = 20 log A V = 20 log (A V ) (A V ) = 20 log A V

  • 20 log A V Can be rewritten as: A V(dB) = A V1(dB)
  • A V2(dB)
  • the total decibel voltage gain of two cascaded stages equals the sum of the individual decibel voltage gains
  • additive property of decibel gain example: What is the total voltage gain in the figure? Express this in decibels. Next, calculate the decibel voltage gain of each stage and the total decibel voltage gain.

IMPEDANCE MATCHING

๏ƒ’ Concept of Impedance Matching