Docsity
Docsity

Prepare for your exams
Prepare for your exams

Study with the several resources on Docsity


Earn points to download
Earn points to download

Earn points by helping other students or get them with a premium plan


Guidelines and tips
Guidelines and tips

Solving Linear Equations: A Collection of Examples, Study notes of Algebra

Solutions to 60 linear equations, each represented by an equation and its corresponding answer. The equations cover various forms, including simple equations, equations with constants, and equations with variables on both sides. Students can use this resource to check their work or understand the solution process for various types of linear equations.

Typology: Study notes

2009/2010

Uploaded on 02/24/2010

koofers-user-j7u
koofers-user-j7u ๐Ÿ‡บ๐Ÿ‡ธ

1

(1)

10 documents

1 / 3

Toggle sidebar

This page cannot be seen from the preview

Don't miss anything!

bg1
Chapter 2 Sections 1, 2, 3, 4 โ€” Linear Equations
E. White
Solve each equation for the indicated variable.
(1) xโˆ’12 = 10 (2) 6 x= 42
(3) x
2= 3 (4) a x =bfor x
(5) 2 aโˆ’1 = 5 (6) โˆ’12 = 0.3tโˆ’9
(7) 5 โˆ’3y= 8 (8) 0.06 s= 0.3
(9) 3 x=1
3(10) a+b=cfor b
(11) 8 xโˆ’12 = โˆ’2 (12) 3.4xโˆ’2.9x= 0.25
(13) a b โˆ’c= 0 for a(14) โˆ’18 t= 27
(15) 3 a+ 28.6=7.8aโˆ’5 (16) 2 (xโˆ’2) = 5
(17) x
2=2
9(18) 3 (x+ 1) = 2 (xโˆ’2)
(19) 3 xโˆ’1 = 3 (xโˆ’2) (20) x y =a b for a
(21) 1
2z+ 2 = 5 (22) 2 xโˆ’3 (x+ 1) = 4
(23) 0.21 b+ 0.5=6.8 (24) a x โˆ’b=afor x
(25) x
4=x
2(26) โˆ’6x+ 5 = โˆ’8xโˆ’12
(27) 5
s=โˆ’2 (28) 2
3x= 6
(29) c
d=a
bfor b(30) 5
6aโˆ’
1
2=1
3
(31) 2 (3 xโˆ’2) = โˆ’4 (xโˆ’2) (32) 2 + 5 (3 x+ 1) = 4
pf3

Partial preview of the text

Download Solving Linear Equations: A Collection of Examples and more Study notes Algebra in PDF only on Docsity!

Chapter 2 Sections 1, 2, 3, 4 โ€” Linear Equations

E. White

Solve each equation for the indicated variable.

(1) x โˆ’ 12 = 10 (2) 6 x = 42

x 2 = 3 (4) a x = b for x

(5) 2 a โˆ’ 1 = 5 (6) โˆ’12 = 0. 3 t โˆ’ 9

(7) 5 โˆ’ 3 y = 8 (8) 0. 06 s = 0. 3

(9) 3 x =

3 (10)^ a^ +^ b^ =^ c^ for^ b

(11) 8 x โˆ’ 12 = โˆ’ 2 (12) 3. 4 x โˆ’ 2. 9 x = 0. 25

(13) a b โˆ’ c = 0 for a (14) โˆ’ 18 t = 27

(15) 3 a + 28.6 = 7. 8 a โˆ’ 5 (16) 2 (x โˆ’ 2) = 5

x 2

(18) 3 (x + 1) = 2 (x โˆ’ 2)

(19) 3 x โˆ’ 1 = 3 (x โˆ’ 2) (20) x y = a b for a

z + 2 = 5 (22) 2 x โˆ’ 3 (x + 1) = 4

(23) 0. 21 b + 0.5 = 6. 8 (24) a x โˆ’ b = a for x

(25) x 4 = x 2 (26) โˆ’ 6 x + 5 = โˆ’ 8 x โˆ’ 12

s

x = 6

c d

a b for b (30)

a โˆ’

(31) 2 (3 x โˆ’ 2) = โˆ’4 (x โˆ’ 2) (32) 2 + 5 (3 x + 1) = 4

(33) 4 (0. 5 s โˆ’ 1 .2) = 5. 2 (34)

x + a = 3 for x

a +

a =

(36) 3(2x โˆ’ 1) = 2(3x โˆ’ 1) โˆ’ 1

c + 3 =

c (38)^0.^2 x^ โˆ’^6 .3 = 1.2 + 0.^1 x

(39) z^ โˆ’^1 3 = 2 z +^1 2 (40) a (b + c) = d for c

(41) 2 s 5

=^7

(42) 2(x + 2) โˆ’ 4 = 2x

(43) 1 .2 (3 x โˆ’ 2) = 26. 4 (44) 12 x = โˆ’ 6 x

a โˆ’

a (46)

2 x โˆ’ 1

(47) 12 (2 x โˆ’ 3) = 24 (x + 2) (48) a (b + c) = b (a + d) for d

(49) .3(4x โˆ’ 1) = 2. 7 (50) 0 .2 (0. 3 s) โˆ’ 2 = 10

a 2 +^

b 3 =^ c^ for^ b^ (52)^ โˆ’3 (5^ โˆ’^ x) + 8 = 0

(53) 6 x =^5 7 (54) 3 .12 (3 x โˆ’ 21) = 0

(55) โˆ’4 (2 x โˆ’ 1) + 1 = x (56) 2 x + 2b โˆ’ 3 = 5b + y for b

2 p โˆ’ 3 2 p + 3 = 2 (58) 3 (p + 2 q) = 7 q for p

a + b c

for a (60) 3. 3 โˆ’ 2 .3 (0. 2 x) = 0. 2 x