# A ball is thrown toward a cliff of height with a speed of 31 and an

February 19th, 2013 05:01
in Advanced Physics by (Albany State University (GA), Chemistry)

## A ball is thrown toward a cliff of height with a speed of 31 and an angle of 60 above horizontal. It lands on?

"A ball is thrown toward a cliff of height h with a speed of 31 m/s and an angle of 60 degrees above horizontal. It lands on the edge of the cliff 3.7 laters.

a) how high is the cliff

b) what is the ball's impact speed ?

thank you"

February 25th, 2013 07:32
(University of Cambridge, Microbiology)
"∆y = h? V_oy = sin60(31) = 31√3/2 V_fy = 0 (pretty sure its safe to assume that it barely reached the cliff, so Vfy = 0) t = 3.7 s a = -9.8 m/s^2 ∆y = V_o * t + (1/2)at^2 ∆y = (31√3/2)(3.7) + (1/2)(-9.8)(3.7^2) ∆y = h = 32.25 m Now to find impact speed i just said V_fy = 0, so there must be some V_fx. ∆x? V_ox = 31cos60 = 31/2 V_fx = ? t = 3.7 s (same time as for y) a = 0 (In free fall there is only acceleration in the y direction, no x) V = V_o + at but since a = 0, there is nothing messing up the x directions trajectory since we are ignoring air resistance. So it will have the same velocity of: Vo = Vf = 31cos60 = 31/2 = 15.5 m/s"

April 16th, 2013 07:33
(Bengal Engineering & Science University, Computer sciences)
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April 16th, 2013 09:57
(Birla Institute of Technology and Science, Computer sciences)
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April 23th, 2013 12:53
(Bengal Engineering & Science University, Electrical Engineering)
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April 25th, 2013 09:14
(Biju Patnaik University of Technology, Rourkela, Aerospace engineering)
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May 6th, 2013 13:59
(Gandhi Institute of Technology and Management, Management)
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