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The radius of the Earth is about 6.37 × 106 m. a) What is the centripetal acceleration of a point on the equat?

"The radius of the Earth is about 6.37 × 10^6 m.

a) What is the centripetal acceleration of

a point on the equator due to the rotation of

earth about its axis?

Answer in units of m/s2

and

b) What is the centripetal acceleration of a

point at the North Pole?

Answer in units of m/s2"

Answers (6)

dewaan 06-03-2013
"Centripetal acceleration is given by a=v^2/r We also know v=w*r and w=2Pi/T, where v=speed, r=radius, w=angular frequency, T=the period=24hrs. Solve for ""a"" in terms of T and r a=(w^2)*r=r*(2*Pi/T)^2 When at the equator r=radius of the earth and at the North Pole r=0"
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shoki_sho 15-05-2013
"twenty-nine. A big dipper cable car loaded with people, incorporates a mass associated with five hundred kg; the spoke regarding curvature from the monitor in the bottom point of a drop is 12 mirielle. The auto has a rate regarding 20 mirielle/azines now. "     
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