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The radius of the Earth is about 6.37 × 106 m. a) What is the centripetal acceleration of a point on the equat?

"The radius of the Earth is about 6.37 × 10^6 m.

a) What is the centripetal acceleration of

a point on the equator due to the rotation of

earth about its axis?

Answer in units of m/s2

and

b) What is the centripetal acceleration of a

point at the North Pole?

Answer in units of m/s2"

Answers (6)

dewaan 06-03-2013
"Centripetal acceleration is given by a=v^2/r We also know v=w*r and w=2Pi/T, where v=speed, r=radius, w=angular frequency, T=the period=24hrs. Solve for ""a"" in terms of T and r a=(w^2)*r=r*(2*Pi/T)^2 When at the equator r=radius of the earth and at the North Pole r=0"
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shoki_sho 15-05-2013
"twenty-nine. A big dipper cable car loaded with people, incorporates a mass associated with five hundred kg; the spoke regarding curvature from the monitor in the bottom point of a drop is 12 mirielle. The auto has a rate regarding 20 mirielle/azines now. "     
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ekmbr 16-05-2013
"30. Is there a speed of the piece of airborne debris with an aged-fabricated phonograph album, xv centimeter from your center field, if your report will be content spinning on 33.iii rpm? "
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masti 27-05-2013
Since center field on the lap (discover diagram) can be previously mentioned this individuals, so the two web drive along with the quickening vectors have an upward way.     
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janam 29-05-2013
"Every single atom of make a difference from the universe draws in another corpuscle having a force out that is right relative towards product or service in their people and reciprocally relative on the rectangular with their separation. "
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raghav 01-06-2013
  "Absolutely no subscript should be applied around the Fs, considering that the push is identical on both masses with value, although other inwards steering (remember Newton’azines 3 rd legislations). According to Newton's Newton's law of gravitation: "
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